25x^2-3x+36=-63x

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Solution for 25x^2-3x+36=-63x equation: 



25x^2-3x+36=-63x

We move all terms to the left:

25x^2-3x+36-(-63x)=0

We get rid of parentheses

25x^2-3x+63x+36=0

We add all the numbers together, and all the variables

25x^2+60x+36=0

a = 25; b = 60; c = +36;
Δ = b2-4ac
Δ = 602-4·25·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-60}{50}=-1+1/5$

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